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Addition Reactions of Alkynes

Hydrohalogenation, hydration, and reduction of the triple bond.

Quick answer Alkynes add reagents across the triple bond much like alkenes, but they can add twice and the products often tautomerize. The key controls to memorize: Markovnikov hydration → ketone, anti-Markovnikov (hydroboration) → aldehyde, Lindlar → cis alkene, Na/NH3 → trans alkene.

A representative example — structures drawn live.

Hydrohalogenation (adding HX)

Hydrogen halides (HCl, HBr, HI) add across a triple bond following Markovnikov's rule: the hydrogen goes to the carbon with more hydrogens, and the halogen goes to the more substituted carbon, which builds the more stable vinyl cation. With one equivalent you get a vinyl halide (a haloalkene).

With two equivalents of HX, addition happens twice. Both halogens end up on the same carbon — the original more-substituted carbon — giving a geminal dihalide (gem-dihalide). For a terminal alkyne like propyne, 2 HBr gives 2,2-dibromopropane.

Acid-catalyzed hydration → ketone

Treating an alkyne with water under acid catalysis with a mercury(II) catalyst (H2O, H2SO4, HgSO4) adds water across the triple bond with Markovnikov regiochemistry. The OH lands on the more substituted carbon, giving an enol (a C=C bearing an OH).

Enols are unstable and immediately tautomerize — a proton and the double bond shift — to the more stable carbonyl form. For a Markovnikov enol, that carbonyl is a ketone. So terminal alkynes give methyl ketones, and internal alkynes give ketones as well (a symmetrical internal alkyne gives a single ketone; an unsymmetrical one gives a mixture).

Hydroboration–oxidation → aldehyde

The anti-Markovnikov complement uses a borane (often a bulky one such as disiamylborane) followed by H2O2/NaOH. Boron adds to the less substituted carbon, so after oxidation the OH ends up there, giving an anti-Markovnikov enol.

That enol tautomerizes to a carbonyl too — but because the oxygen is now on the terminal carbon, a terminal alkyne gives an aldehyde rather than a ketone. This is the standard way to convert a terminal alkyne into an aldehyde. The contrast is worth memorizing: Markovnikov hydration → ketone; hydroboration → aldehyde.

Reduction: controlling cis vs. trans

You can partially or fully reduce a triple bond, and the reagent dictates the stereochemistry of the alkene you get:

  • H2 with Lindlar catalyst (poisoned Pd) stops at the alkene and delivers both hydrogens to the same face — a syn addition giving the cis (Z) alkene.
  • Na (or Li) in NH3 — dissolving-metal reduction — proceeds through a radical/anion pathway and gives the trans (E) alkene.
  • H2 with Pd/C (ordinary catalyst) does not stop; it reduces all the way to the alkane.

Reagent → product cheat sheet

For a terminal alkyne, here is the quick map:

  • 1 eq HX → vinyl halide (Markovnikov); 2 eq HX → geminal dihalide.
  • H2O, H2SO4, HgSO4 → methyl ketone (via Markovnikov enol).
  • 1) R2BH; 2) H2O2, NaOH → aldehyde (via anti-Markovnikov enol).
  • H2, Lindlar → cis alkene; Na, NH3 → trans alkene; H2, Pd/C → alkane.

Keep two themes in mind across all of these: alkynes can add twice, and enol intermediates always tautomerize to the carbonyl. Get those two ideas plus the four regio/stereochemistry controls above, and alkyne addition problems become predictable.

Draw this on the whiteboard

Open the OChem Board whiteboard — benzene rings, curved arrows, wedge/dash bonds and a clickable periodic table built in. No account needed.

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