Learn · Organic Chemistry

1,2- vs 1,4-Addition to Conjugated Dienes

One HBr, two products — a resonance-stabilized allylic cation lets the bromide trap either end, and temperature decides which one wins.

Quick answer Adding one equivalent of HBr to a conjugated diene gives two constitutional products because the intermediate is a resonance-stabilized allylic cation whose positive charge is shared over two carbons, so bromide can trap either end. Low temperature favors the faster-forming 1,2-adduct (kinetic product), while high, reversible conditions favor the more stable, more-substituted 1,4-adduct (thermodynamic product).

1. One Equivalent of HBr Gives a Conjugated Diene Two Products

Adding a single HBr across 1,3-butadiene produces two constitutional isomers at once — the 1,2-adduct and the 1,4-adduct — not one clean product.

1,3-Butadiene + one equivalent of HBr — the same reaction also yields the 1,4-adduct shown below.

2. The Split Comes From a Resonance-Stabilized Allylic Cation

After H+ adds to an end carbon, the resulting cation is allylic, so its positive charge is delocalized over two carbons by resonance.

Allyl cation — charge on the terminal carbon
Resonance form — charge on the other carbon

3. Bromide Traps the Nearer Carbon for the 1,2-Adduct

When Br- attacks the carbon next to where H added, the addition spans one original double bond and gives 3-bromo-1-butene.

1,2-Adduct — 3-bromo-1-butene (double bond at the end)

4. Bromide Traps the Far Carbon for the 1,4-Adduct

When Br- attacks the far end of the shared system, the H and Br land on carbons 1 and 4, leaving a new double bond in the middle.

1,4-Adduct — 1-bromo-2-butene (double bond in the middle)

5. Temperature Chooses: Cold Gives Kinetic, Hot Gives Thermodynamic

Low temperature favors the faster-forming 1,2-adduct (kinetic), while high, reversible temperature favors the more-substituted, more stable 1,4-adduct (thermodynamic).

1,2 — kinetic product, wins in the cold
1,4 — thermodynamic product, wins when hot

6. Summary

One HBr, two products · allylic cation shares charge over two carbons · 1,2 traps the near carbon · 1,4 leaves the double bond in the middle · cold → kinetic 1,2 · hot → thermodynamic 1,4 · builds on conjugation and stability and the Diels–Alder reaction.

Quiz yourself

Tap a question to reveal the answer — free, no login.

Because H+ adds first to make an allylic cation whose positive charge is delocalized over two carbons by resonance. Bromide can then attack either of those two carbons, so you get two constitutional isomers — the 1,2- and 1,4-adducts.

The 1,4-adduct (1-bromo-2-butene). H and Br add to carbons 1 and 4 of the conjugated system, which leaves a double bond between carbons 2 and 3 — right in the middle. The 1,2-adduct instead keeps the double bond at the end.

The 1,2-adduct — it is the kinetic product. At low temperature the reaction is effectively irreversible, so the product that forms faster (bromide traps the nearer, higher-charge-density carbon) accumulates, even though it is slightly less stable.

At high temperature the addition becomes reversible, so the system equilibrates to the more stable product. The 1,4-adduct has a more-substituted (internal) double bond, which is thermodynamically more stable, so it wins under thermodynamic control.

Draw this on the whiteboard

Open the OChem Board whiteboard — benzene rings, wedge/dash bonds, and a clickable periodic table built in. No account needed.

Open the whiteboard →