Learn · Organic Chemistry

Key Reactions of Alcohols

Substitution, elimination, oxidation, and turning a poor OH leaving group into a good one.

Quick answer The –OH is a poor leaving group, so every alcohol reaction starts by fixing that — protonate it to water, or swap it for a halide or tosylate. Then alcohols undergo substitution, dehydration to alkenes, and oxidation to carbonyls.
1° alcohol (ethanol)
2° alcohol (2-propanol)
3° alcohol (tert-butanol)

The class of the carbinol carbon — 1°, 2°, or 3° — decides almost everything that follows.

1. The –OH is a poor leaving group, so an alcohol must be activated before it reacts

Hydroxide is a strong base, so it clings to carbon and refuses to leave; the only fixes are to protonate the OH (it leaves as water) or replace it with a halide or tosylate.

–OH: poor
–Br: good
–OTs: excellent

2. Oxidation turns 1° alcohols into aldehydes or acids and 2° alcohols into ketones

Mild anhydrous PCC stops a 1° alcohol at the aldehyde, while strong aqueous oxidants (H2CrO4/Jones, hot KMnO4) drive it to the carboxylic acid.

PCC stops a 1° alcohol at the aldehyde — 1-propanol → propanal.

1-propanol
propanal
propanoic acid

Secondary alcohols oxidize to ketones and stop there; tertiary alcohols do not oxidize — that carbon has no H to lose.

3. SOCl₂ and PBr₃ convert alcohols to alkyl halides without rearrangement

PBr3 gives R–Br and SOCl2 gives R–Cl in one concerted, SN2-like step — no free carbocation, so the skeleton never rearranges.

PBr3 converts 1-propanol to 1-bromopropane — no rearrangement.

4. With HX, protonation lets water leave — but 3° alcohols go SN1 and can rearrange

Concentrated HX protonates the oxygen so water leaves and halide takes its place; 3° alcohols react fast by SN1 through a stable carbocation.

tert-butanol + HCl → 2-chloro-2-methylpropane via a 3° carbocation.

With 2° substrates that cation can undergo a hydride or methyl shift, scrambling the product — which is exactly why PBr3 and SOCl2 exist.

5. Tosylation converts a bad leaving group into an excellent one for SN2 and E2

TsCl/pyridine caps R–OH as a tosylate by attacking the O–H bond, never C–O, so configuration at carbon is retained.

TsCl caps the oxygen — the C–O bond is untouched, so configuration is retained.

The sulfonate spreads its charge over three oxygens, making –OTs a superb leaving group — a launchpad for a clean SN2 or E2.

6. Acid and heat dehydrate an alcohol to the Zaitsev alkene by an E1 path

Strong acid and heat lose water to an alkene by E1: protonate the OH, lose water to a carbocation, then a base plucks a β-hydrogen.

2-propanol dehydrates to propene under conc. H2SO4 and heat.

Protonate the –OH → a good leaving group
Water leaves → 2° carbocation
Base removes a β-H → alkene

Reactivity tracks cation stability (3° > 2° > 1°) and regiochemistry follows Zaitsev's rule — the more substituted alkene dominates.

How each reagent works — the arrow pushing

Electron flow only. Follow the arrows; the structures do the talking.

Oxidation (PCC / H2CrO4) — chromate ester, then E2-like2 steps
Why it works · Chromium starts in its high +6 oxidation state, making it electron-poor (δ+) and a powerful oxidant — it wants electrons. The δ– alcohol oxygen binds Cr to form a chromate ester; then an α C–H is lost as the C=O forms and Cr is reduced (+6 → +4). That electron flow from carbon to chromium is the oxidation. Anhydrous PCC stops a 1° alcohol at the aldehyde; aqueous Jones/H2CrO4 drives on to the acid; 3° alcohols have no α-H and can’t oxidize.
Form the chromate esterCH3CH3HOHCrOOHOH+6
E2-like elimination (redox)CH3CH3HOCrOOHBCH3CH3Oketone
PBr3 — attack at P, backside SN2, inversion3 steps
Why it works · Phosphorus is bonded to three electron-withdrawing bromines, so it is strongly δ+ (electrophilic) — that is the site the alcohol’s δ– oxygen attacks. The released Br is then a good nucleophile for the Sn2. PBr3 is an activator, not a redox reagent: it swaps the terrible –OH leaving group for the O–PBr2 group that bromide can kick off.
Attack at phosphorusCH3CH3HOHPBrBrBr
Backside SN2CH3CH3HO+HPBrBrBr
InversionCH3CH3HBrconfiguration invertedBrBrPOHbyproduct
SOCl2 — attack at S, backside SN2, then SO2 + HCl3 steps
Why it works · Sulfur sits between an S=O and two chlorines pulling electron density off it, so S is δ+ (electrophilic) and the δ– alcohol oxygen attacks there. A freed Cl does the backside Sn2. Also an activator (not redox) — and its leaving group collapses to SO2 + HCl gas, so the equilibrium is pulled all the way to product.
Attack at sulfurCH3CH3HOHSOClCl
Backside SN2CH3CH3HOSOClCl
InversionCH3CH3HClconfiguration invertedSOOSO2 (gas) + HClbyproducts — irreversible
TsCl / pyridine — cap the O, retention at carbon2 steps
Why it works · The sulfonyl sulfur sits between two S=O groups and a Cl pulling electron density off it, so S is strongly δ+ (electrophilic). The δ– alcohol oxygen — not carbon — attacks S, and pyridine mops up the HCl. Because the C–O bond is never touched, configuration is retained. Tosylation is an activator (not redox): –OTs spreads its negative charge over three oxygens, making it one of the best leaving groups — a launchpad for a clean Sn2 or E2.
O attacks S — C–O bond untouchedCH3CH3HOHSCH3OOCl
Pyridine deprotonates → OTs, retentionCH3CH3HO+HTsNpyCH3CH3HOTsconfiguration retained
Acid + heat — dehydration by E13 steps
Why it works · Strong acid supplies H+, a bare electrophile that protonates the δ– oxygen so –OH can leave as neutral water. This is pure Brønsted-acid activation — carbon is neither oxidized nor reduced. Heat and the loss of a small gas/liquid favor elimination over substitution.
CH3CH3OHH+fastCH3CH3OH2+
CH3CH3OH2+slowCH3CH3+2° carbocation
CH3CH3+HBCH3CH3but-2-ene (Zaitsev)

7. Summary

Carbonyl → oxidize (PCC to aldehyde, H2CrO4/KMnO4 to acid, any oxidant for 2° → ketone; 3° won't) · Clean halide → PBr3/SOCl2 · 3° alcohol → HX by SN1 · Set up SN2/E2 → tosylate · Alkene → acid + heat, Zaitsev by E1.

Quiz yourself

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Because –OH is a poor leaving group. Hydroxide is a strong base, so it will not depart from carbon. You must first protonate it (so it leaves as water) or convert it to a halide or tosylate.

PCC (pyridinium chlorochromate) — a mild, anhydrous oxidant. Strong aqueous oxidants like H2CrO4 (Jones) or hot KMnO4 push all the way to the carboxylic acid.

PBr3 reacts by a concerted, SN2-like displacement with no free carbocation, so the skeleton does not rearrange. HBr goes through a carbocation that can undergo hydride/methyl shifts, scrambling the product.

Propene, by E1. The acid protonates the OH, water leaves to give a 2° carbocation, and a base removes a β-hydrogen to form the alkene (Zaitsev product).

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