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Lewis structures and formal charge

Build any Lewis structure in five steps and use formal charge to pick between resonance forms — without memorization.

Quick answer Count total valence electrons, draw a skeleton with single bonds, fill octets with lone pairs starting from the most electronegative atom, convert lone pairs to double or triple bonds if anyone is short, and check formal charges. The best Lewis structure has all formal charges as small and as close to zero as possible.

Step 1: count valence electrons

Sum up the valence electrons of every atom. For an ion, add one electron per negative charge and subtract one per positive charge. For SO₄²⁻: S(6) + 4·O(6) + 2 (for the charge) = 32 electrons.

Step 2: draw the skeleton

Put the least electronegative atom in the middle (usually). Hydrogens go on the outside — never in the middle. Connect each atom with a single bond. Each bond uses two electrons; subtract them from your total.

Step 3: fill octets with lone pairs

Distribute the remaining electrons as lone pairs, starting with the most electronegative atoms on the outside, until every atom has eight (two for H). If you run out before everyone is full, you'll fix it in step 4.

Step 4: convert lone pairs to multiple bonds

If the central atom doesn't have an octet yet, "borrow" a lone pair from a neighbor and turn it into a second bond. You may need triple bonds (N₂, CO) or multiple double bonds (CO₂, SO₃).

Step 5: formal charge check

Formal charge = valence electrons – nonbonding electrons – (bonding electrons / 2). Compute it for every atom. Sum them up — must equal the overall charge of the molecule/ion. The structure with formal charges closest to zero (and negative charges on the most electronegative atoms) is the major resonance contributor.

Draw this on the whiteboard

Open the OChem Board whiteboard — benzene rings, wedge/dash bonds, and a clickable periodic table built in. No account needed.

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